is the expression to be summed really |sin(4n/π)+3|/4^n,
or is it
|sin(4nπ)+3|/4^n?
I have to get the result of the serie from 1 to infinite of
|sin(4n/π) +3|/ 4^n
I really don't know what to do...
Please I would really appreciate if anyone can help me
3 answers
It's |sin(4n/π)+3|/4^n
clearly, the series converges, since
|sin(4n/π)+3|/4^n < |1+3|/4^n
which converges to 16/3
But I can't come up with the actual limit value.
|sin(4n/π)+3|/4^n < |1+3|/4^n
which converges to 16/3
But I can't come up with the actual limit value.