Asked by Anne
                I have to get the result of the serie from 1 to infinite of
|sin(4n/π) +3|/ 4^n
I really don't know what to do...
Please I would really appreciate if anyone can help me
            
        |sin(4n/π) +3|/ 4^n
I really don't know what to do...
Please I would really appreciate if anyone can help me
Answers
                    Answered by
            MathMate
            
    is the expression to be summed really |sin(4n/π)+3|/4^n,
or is it
|sin(4nπ)+3|/4^n?
    
or is it
|sin(4nπ)+3|/4^n?
                    Answered by
            Anne
            
    It's  |sin(4n/π)+3|/4^n
    
                    Answered by
            Steve
            
    clearly, the series converges, since
|sin(4n/π)+3|/4^n < |1+3|/4^n
which converges to 16/3
But I can't come up with the actual limit value.
    
|sin(4n/π)+3|/4^n < |1+3|/4^n
which converges to 16/3
But I can't come up with the actual limit value.
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