To find the perimeter of rectangle HIJK, we first need to determine the lengths of its sides.
The coordinates of the vertices are:
- \( I = (2, 2) \)
- \( J = (6, 2) \)
- \( K = (6, -7) \)
- \( H = (2, -7) \)
Now we can calculate the lengths of the sides:
-
Length of side IJ: \[ IJ = x_J - x_I = 6 - 2 = 4 \text{ units} \]
-
Length of side IH (or JK): \[ IH = y_I - y_H = 2 - (-7) = 2 + 7 = 9 \text{ units} \]
The perimeter \( P \) of a rectangle is given by the formula: \[ P = 2 \times (\text{Length} + \text{Width}) \] In this case, the Length is 4 units, and the Width is 9 units.
Now let's calculate the perimeter: \[ P = 2 \times (4 + 9) = 2 \times 13 = 26 \text{ units} \]
Thus, the perimeter of rectangle HIJK is \( \boxed{26} \) units.
2 answers