The perimeter of a rectangle is 76 feet. If the width is doubled and the length is halved, the new rectangle will have a perimeter of 62 feet. Find the dimensions of the original rectangle. Define your variables.

Answer 1

old rectangle:
length : y
width : x
so 2x + 2y = 76 or
x+y = 38

new rectangle:
2x by y/2

2(2x) + 2(y/2) = 62
4x + y = 62

subtract them:
3x = 24
x = 8 ,then y = 30