What is the energy of a photon with a frequency of 1.7 × 1017 Hz? Planck’s constant is 6.63 × 10–34 J•s.

1.1 × 10–17 J
1.1 × 10–16 J
8.3 × 10–16 J
8.3 × 10–15 J

1 answer

To find the energy of a photon given its frequency, you can use the formula:

\[ E = h \cdot f \]

where:

  • \(E\) is the energy of the photon,
  • \(h\) is Planck's constant (\(6.63 \times 10^{-34} , \text{J s}\)),
  • \(f\) is the frequency of the photon (\(1.7 \times 10^{17} , \text{Hz}\)).

Now we can calculate the energy:

\[ E = (6.63 \times 10^{-34} , \text{J s}) \times (1.7 \times 10^{17} , \text{Hz}) \]

Calculating this:

\[ E = 6.63 \times 1.7 \times 10^{-34 + 17} , \text{J} \] \[ E = 11.271 \times 10^{-17} , \text{J} \]

Now adjusting the exponent:

\[ E = 1.1271 \times 10^{-16} , \text{J} \]

This can be rounded to:

\[ E \approx 1.1 \times 10^{-16} , \text{J} \]

Thus, the energy of the photon is 1.1 × 10–16 J.