A photon has a frequency of 2.9 × 10–16 Hz. Planck’s constant is 6.63 × 10–34 J•s.

The energy of the photon, to the nearest tenths place, is

1 answer

To calculate the energy of a photon, you can use the formula:

\[ E = h \cdot f \]

where:

  • \( E \) is the energy of the photon,
  • \( h \) is Planck's constant (\( 6.63 \times 10^{-34} , \text{J}\cdot\text{s} \)),
  • \( f \) is the frequency of the photon (\( 2.9 \times 10^{-16} , \text{Hz} \)).

Now, let's plug in the values:

\[ E = (6.63 \times 10^{-34} , \text{J}\cdot\text{s}) \cdot (2.9 \times 10^{-16} , \text{Hz}) \]

Now, calculate \( E \):

\[ E = 6.63 \times 2.9 \times 10^{-34} \times 10^{-16} \]

Calculating \( 6.63 \times 2.9 \):

\[ 6.63 \times 2.9 = 19.227 \]

Now, multiply the powers of 10:

\[ 10^{-34} \times 10^{-16} = 10^{-50} \]

Now, assemble it all together:

\[ E = 19.227 \times 10^{-50} , \text{J} \]

To express this in scientific notation:

\[ E = 1.9227 \times 10^{-49} , \text{J} \]

Now, rounding to the nearest tenths place:

\[ E \approx 1.9 \times 10^{-49} , \text{J} \]

Thus, the energy of the photon, to the nearest tenths place, is:

\[ \boxed{1.9 \times 10^{-49}} , \text{J} \]