A photon has 8.0 × 10–15 J of energy. Planck’s constant is 6.63 × 10–34 J•s.

What is the frequency of the photon?

1.21 × 1019 Hz
8.3 × 10–20 Hz
1.21 × 10–19 Hz
8.3 × 1020 Hz

1 answer

To find the frequency of the photon, we can use the formula that relates energy (E), frequency (ν), and Planck’s constant (h):

\[ E = h \cdot \nu \]

Where:

  • \(E\) is the energy of the photon,
  • \(h\) is Planck's constant (\(6.63 \times 10^{-34} , \text{J·s}\)),
  • \(ν\) is the frequency of the photon.

We can rearrange this formula to solve for frequency:

\[ ν = \frac{E}{h} \]

Substituting the known values:

\[ ν = \frac{8.0 \times 10^{-15} , \text{J}}{6.63 \times 10^{-34} , \text{J·s}} \]

Calculating this gives:

\[ ν = \frac{8.0 \times 10^{-15}}{6.63 \times 10^{-34}} \approx 1.21 \times 10^{19} , \text{Hz} \]

Therefore, the frequency of the photon is approximately:

\[ \boxed{1.21 \times 10^{19} , \text{Hz}} \]

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