25*.1 + 50*.05 = (25+50)*x
Where did you get that 5?
What is the concentration (M) of K+ in a solution made by mixing 25.0 mL of 0.100 M KCl with 50.0 mL of 0.0500 M KCl?
Can you please explain how to solve this problem.
I thought to do 25*.1+50*.05=5
But that seems wrong. What should I try to do?
3 answers
25/1000*0.1=0.025 mole Kcl
50/1000*0.05=0.025 mole Kcl
1 mole KCl-39g K+
0.025 moleKCl- 0.975g K+
0.975/74.5=0.013
total mole=0.013*2=0.026
total volume=0.025+0.05=0.075
Concentration K+=mole/volume
concentration=0.026/0.075
=0.35M
50/1000*0.05=0.025 mole Kcl
1 mole KCl-39g K+
0.025 moleKCl- 0.975g K+
0.975/74.5=0.013
total mole=0.013*2=0.026
total volume=0.025+0.05=0.075
Concentration K+=mole/volume
concentration=0.026/0.075
=0.35M
pardon me
25/1000*0.1=0.025 mole Kcl
50/1000*0.05=0.025 mole Kcl
1 mole KCl-39g K+
0.025 moleKCl- 0.975g K+
0.975/39=0.025
total mole=0.025*2=0.05
total volume=0.025+0.05=0.075
Concentration K+=mole/volume
concentration=0.05/0.075
=0.67M
25/1000*0.1=0.025 mole Kcl
50/1000*0.05=0.025 mole Kcl
1 mole KCl-39g K+
0.025 moleKCl- 0.975g K+
0.975/39=0.025
total mole=0.025*2=0.05
total volume=0.025+0.05=0.075
Concentration K+=mole/volume
concentration=0.05/0.075
=0.67M
2 answers