Concentration of OH- left in a solution made by mixing 16.0 g of NaOH and 80.0 mL of 0.170M HNO3?

Answer 1

HNO3 + NaOH ==> NaNO3 + H2O
moles HNO3 = M x L = 0.0136
moles NaOH = g/molar mass = 16/40 = 0.4

So all of the HNO3 will be used up and NaOH remaining will be 0.400 - 0.0136 = ??
and molarity = moles/L = ??