success

This page lists questions and answers that were posted by visitors named success.

Questions

The following questions were asked by visitors named success.

Answers

The following answers were posted by visitors named success.

0.1
13 years ago
R=2GM/C^2 R=[2*6.67*10^-1*1.68*10^43]/9*10^16 R=2.5*10^16m
10 years ago
S=at/2. 77=5t^2 t=15.4s range=vt R=261.8m
10 years ago
2C4H10 + 13O2---> 8CO2 + 10H2O Rmm of 1 mole oxygen=32g 13 mole=416g mass of 1 mole of butane=58g 2 mole=116g 116g C4H10 requires 416g O2 17.8 C4H10 will require 64g O2 excess butane=29.1-17.8=11.3g
10 years ago
density=mass/volume 13.55*3.2=43.36g 1 mole of Hg=200.59 0.2 mole=43.36g mole=number of atom/avogadroes number atom=0.2*6.02*10^23 atom=1.204*10^23
10 years ago
25/1000*0.1=0.025 mole Kcl 50/1000*0.05=0.025 mole Kcl 1 mole KCl-39g K+ 0.025 moleKCl- 0.975g K+ 0.975/74.5=0.013 total mole=0.013*2=0.026 total volume=0.025+0.05=0.075 Concentration K+=mole/volume concentration=0.026/0.075 =0.35M
10 years ago
pardon me 25/1000*0.1=0.025 mole Kcl 50/1000*0.05=0.025 mole Kcl 1 mole KCl-39g K+ 0.025 moleKCl- 0.975g K+ 0.975/39=0.025 total mole=0.025*2=0.05 total volume=0.025+0.05=0.075 Concentration K+=mole/volume concentration=0.05/0.075 =0.67M
10 years ago
R^2= y^2+ x^2 R^2=300^2+50^2 R^2=90,000+2,500 R^2=√92,500 R=304.14km/h
9 years ago
By providing social amenities
7 years ago
waiting for answer
6 years ago
thank
4 years ago
is it the full
3 years ago
An aircraft flew from to p to another q85km north of p. the aircraft then flew eastward from p. if the average speed of the plane is 700km 1.\PT/ the total time taken for the journey.
2 years ago
A close tin is the shape of a cylinder of diameter10cm and height15cm,use the value3.14for ^to find the total surface area of the in
2 years ago