mass Hg = volume x density = ?
200.59 g Hg contains 6.02E23 atoms Hg. So ? g Hg will have ...... atoms Hg.
How many atoms of mercury are present in
3.2 cubic centimeters of liquid mercury?
The density of mercury is 13.55 g/cc.
Answer in units of atoms.
2 answers
density=mass/volume
13.55*3.2=43.36g
1 mole of Hg=200.59
0.2 mole=43.36g
mole=number of atom/avogadroes number
atom=0.2*6.02*10^23
atom=1.204*10^23
13.55*3.2=43.36g
1 mole of Hg=200.59
0.2 mole=43.36g
mole=number of atom/avogadroes number
atom=0.2*6.02*10^23
atom=1.204*10^23
2 answers