If x=-4 and x = -1 are zeros to one or more of the given functions, then dividing them by both x+1 and x+4 should yield a remainder of zero.
I divided x+1 into each of the given functions (I used synthetic division), each yielded a remainder.
So x+1 did not divide into any of them
I suspect either a typo, or the question is flawed (or I made an error in my calculation)
What is a quartic function with only the two real zeros given?
x = -4 and x = -1
A. y = x^4 + 5x^3 + 5x^2 + 5x + 4
B. y = x^4 - 5x^3 - 5x^2 - 5x - 4
C. y = -x^4 + 5x^3 + 5x^2 + 5x + 4
D. y = x^4 + 5x^3 + 5x^2 + 5x - 5
1 answer