This is an example of "gouping"
4x^3-24x^2-x+6
= 4x^2(x-6) - (x-6)
= (x-6)(x^2 - 1) , now by difference of squares
= (x-6)(x-1)(x+1)
How do you factor a quartic equation such as 4x^3-24x^2-x+6. Could you break it down step by step? thank you.
2 answers
5r-5s
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5r+ 5s
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5r+ 5s