Asked by tabatha
                What is a quartic function with only the two real zeros given?
x = -4 and x = -1
            
            
        x = -4 and x = -1
Answers
                    Answered by
            Steve
            
    y = (x+4)(x+1)^3
y = (x+4)^2 (x+1)^2
y = (x+4)^3 (x+1)
    
y = (x+4)^2 (x+1)^2
y = (x+4)^3 (x+1)
                    Answered by
            tabatha
            
    these are my choices
A. y = x4 + 5x3 + 5x2 + 5x + 4
B. y = x4 - 5x3 - 5x2 - 5x - 4
C. y = -x4 + 5x3 + 5x2 + 5x + 4
D. y = x4 + 5x3 + 5x2 + 5x - 5
    
A. y = x4 + 5x3 + 5x2 + 5x + 4
B. y = x4 - 5x3 - 5x2 - 5x - 4
C. y = -x4 + 5x3 + 5x2 + 5x + 4
D. y = x4 + 5x3 + 5x2 + 5x - 5
                    Answered by
            Steve
            
    well, then you better expand my solutions to see which fits.
    
                    Answered by
            tabatha
            
    I got the answer as and it was right :)
A. y = x4 + 5x3 + 5x2 + 5x + 4
    
A. y = x4 + 5x3 + 5x2 + 5x + 4
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