the vertex tells you that
y = a(x-3)^2 + 6
so now plug in your point to get
a(2-3)^2 + 6 = 4
a = -2
so
y = -2(x-3)^2 + 6 = -2x^2 +12x -12
what is a function of a quadratic that has a vertex at (3,6) and goes through the point (2,4).
1 answer