x'2+ 10= 3x+17. Use the quadratic formula to solve.

2 answers

x'2+ 10= 3x+17

it is generally accepted to use ^ to show exponents.
x^2+ 10= 3x+17
x2 - 3x - 7 = 0

x = (3 ± √(9-4(1)(-7))/2

can you finish it ?
the square root is impossible to do how do you solve it?