Asked by Agatha

Factories the following quadratic equations 10Y2 + 21Y-10
Answered by Isaac

10y²+21y-10=0

10y²+25y-4y-10=0

(10y²+25)-(4y+10)=0

5y(2y+5)-2(2y+5)=0

(5y-2)(2y+5)=0

5y-2=0 or 2y+5=0

Y=2/5 or y=-5/2
Answered by Damon
typo?
(10y²+25)-(4y+10)=0
or
(10y²+25y)-(4y+10)=0
Answered by Isaac
Thanks sir yes it was a typo
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