To find the zeros of the graph of the function given in your message, it appears there was a formatting issue. It seems that the function is intended to be \( y = 2^2 + [5x - 12] - 6 \).
Let's simplify the expression first:
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Rewrite \( y \): \[ y = 4 + (5x - 12) - 6 \] Simplifying this gives: \[ y = 5x - 12 + 4 - 6 \] \[ y = 5x - 14 \]
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Finding the zeros: To find the zeros, set \( y = 0 \): \[ 0 = 5x - 14 \] Solving for \( x \): \[ 5x = 14 \] \[ x = \frac{14}{5} \quad \text{or} \quad 2.8 \]
Therefore, the zero of the function \( y = 5x - 14 \) is at \( x = \frac{14}{5} \) (or 2.8).
Regarding the other values you mentioned (like \( -6, 2, \frac{-3}{5}, 4, \frac{3}{2}, -4, 3, -4 \)), they don't appear relevant to the calculation of zeros unless the context was around specific values of \( x \) to evaluate.
Please clarify if this addresses your question or if you have additional context to provide!
3 answers