What are all the real zeroes of y=(x–12)3–7 ?

Answer 1

The real zeros of a polynomial can be found by setting the polynomial equal to zero and solving for x.

Setting y = 0, we have:
0 = (x-12)^3 - 7

To solve for x, we can add 7 to both sides of the equation:
7 = (x-12)^3

Then, we can take the cube root of both sides:
³√7 = x - 12

Finally, we can add 12 to both sides to isolate x:
x = 12 + ³√7

Therefore, the real zero of y = (x-12)^3 - 7 is x = 12 + ³√7.