Ask a New Question

Question

if zeroes of p(x)=5x^2-7x+k are reciprocal of each other then find value of k
10 years ago

Answers

Steve
using the quadratic formula,

x = [7±√(49-20k)]/10
so,

(7+√(49-20k))/10 * (7-√(49-20k))/10 = 1
49-(49-20k) = 100
20k = 100
k = 5


10 years ago

Related Questions

How would you find the zeroes for this? x^2+3x-9 What are the zeroes of f(x) = 2x^2 -3x + 1 If one of the zeroes of the cubic polynomial x3+ax2+bx+c is -1 then the product of the other two zer... What are the zeroes of y = x2 + 2x – 8? –4, 2 4, –2 –4, –2 4, 2 What are the zeroes of y=x2−2x−15%0D%0A%0D%0A=%0D%0A%0D%0A2%0D%0A−%0D%0A2%0D%0A%0D%0A−%0D%0A15%0D%0A... What are the zeroes of `y=x^{2}-x-20`? <--- SHOW YOUR WORK What would be the zeroes of the function 𝑓(𝑥) = 𝑥^2 + 5𝑥 − 24 a. -8 and 3 b. -8 and -3 c. 8 and -... What are the zeroes of f(x) = x2 + 5x + 6? x = −2, −3 x = 2, 3 x = −2, 3 x = 2, −3
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use