Asked by noaf
if zeroes of p(x)=5x^2-7x+k are reciprocal of each other then find value of k
Answers
Answered by
Steve
using the quadratic formula,
x = [7±√(49-20k)]/10
so,
(7+√(49-20k))/10 * (7-√(49-20k))/10 = 1
49-(49-20k) = 100
20k = 100
k = 5
x = [7±√(49-20k)]/10
so,
(7+√(49-20k))/10 * (7-√(49-20k))/10 = 1
49-(49-20k) = 100
20k = 100
k = 5
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