Asked by noaf
                if zeroes of p(x)=5x^2-7x+k are reciprocal of each other then find value of k
            
            
        Answers
                    Answered by
            Steve
            
    using the quadratic formula,
x = [7±√(49-20k)]/10
so,
(7+√(49-20k))/10 * (7-√(49-20k))/10 = 1
49-(49-20k) = 100
20k = 100
k = 5
    
x = [7±√(49-20k)]/10
so,
(7+√(49-20k))/10 * (7-√(49-20k))/10 = 1
49-(49-20k) = 100
20k = 100
k = 5
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