For the first three, you would have to apply the rational zero theorem then use synthetic division to see if the remainder is zero.
For the last two, you would group the terms and factor out a common factor method(http://www.chesapeake.edu/khennayake/MAT113/3.2Solution.htm).
find all the zeroes of:
x^5-3x^4-24x^3-72x^2-25x+75=0
5x^5-20x^4-40x^3-16x^2-45x+180=0
-3x^5+3x^4+9x^3-7x^2+12x=12
x^3-x^2-13x-13=0
x^3+x^2=15x-15
Thank you for any help...I'm desperate please help :(
2 answers
This was done by trial and error assisted by EXCEL. Very tedious!
1.Solution Set: X =-1.5887,0.7772,-1.2089, and 0.8717.
2.X = -2.07316,1.2139,-5.0432, and 2.2307.
3. X = -1.9548,2.1191, and 0.9050.
4. X = -2.218,4.516,-11.908,-1.0917.
5. x^3+x^2 = 15x-15.
x^3+x^2-15x+15 = 0.
NOTE: All values of X shown are called
ZEROES, because they give zero output
when plugged into the Eq.
I hope I've helped.
X = -2.218,1.220,13.923,1.0774.
1.Solution Set: X =-1.5887,0.7772,-1.2089, and 0.8717.
2.X = -2.07316,1.2139,-5.0432, and 2.2307.
3. X = -1.9548,2.1191, and 0.9050.
4. X = -2.218,4.516,-11.908,-1.0917.
5. x^3+x^2 = 15x-15.
x^3+x^2-15x+15 = 0.
NOTE: All values of X shown are called
ZEROES, because they give zero output
when plugged into the Eq.
I hope I've helped.
X = -2.218,1.220,13.923,1.0774.
1 answer