technicality here
from (x+1)^2
we have (x+1)(x+1)
so x = -1 or x = -1
same root shows up twice, so they call it a multiplicity of 2
your zeros are correct
find the zeroes and state the multiplicity of multiple zeroes
y=(x+1)^2 (x-1) (x-2)
I know that
x=-1
x=1
x=2
I don't know how to find the multiplicities
1 answer