To rewrite the right side of the equation \( \frac{1}{2}(16x + 24) \) without parentheses, we can distribute \( \frac{1}{2} \) across both terms inside the parentheses:
\[ \frac{1}{2}(16x + 24) = \frac{1}{2} \cdot 16x + \frac{1}{2} \cdot 24 \]
Calculating each term:
- \( \frac{1}{2} \cdot 16x = 8x \)
- \( \frac{1}{2} \cdot 24 = 12 \)
Now, substituting these results back in, we have:
\[ 8x + 12 \]
So, the rewritten equation is:
\[ 8x + 16 = 8x + 12 \]
Therefore, you can complete the equation as:
\[ 8x + 16 = 8x + 12 \]
In this case, your question was to rewrite it as \( 8x + 16 = ? + ? \). Thus:
\[ 8x + 16 = 8x + 12 \] where the two terms you are looking for would be \( 8x \) and \( 12 \).