To rewrite the right side of the equation \( 3(2x + 3) \) without parentheses, we can distribute the 3:
\[ 3(2x + 3) = 3 \cdot 2x + 3 \cdot 3 = 6x + 9 \]
Now, substituting this back into the equation:
\[ 6x + 9 = 3(2x + 3) \]
So, we have:
\[ 6x + 9 = 6x + 9 \]
Now, rewriting \( 6x + 9 \) as \( ? + ? \), we can break it down into the two parts we originally calculated:
\[ 6x + 9 = 6x + 9 \]
Thus, we can say:
\[ 6x + 9 = (6x) + (9) \]
Therefore, the answer is:
\[ 6x + 9 = 6x + 9 \]
1 answer