Water is added to two containers for 16 minutes. The equations below model the ounces of water, y, in each container after x minutes. At the time after the start when the containers hold the same amount of water, how much water do they hold?

Question

Water is added to two containers for 16 minutes. The equations below model the ounces of water, y, in each container after x minutes. At the time after the start when the containers hold the same amount of water, how much water do they hold?
Container A: y= 16x+104
Container B: y= -2x²+40x+160

A. 360 oz.
B. 328 oz.
C. 232 oz.
D. 136 oz.

Damon · Accepted Answer

well when is the amount in A equal to the amount in B ??
16 x + 104 = -2 x^2 + 40 x + 160
well first divide everything by 2 to make it easy
8 x + 52 = - x^2 +20 x + 80
now put everything on the left
x^2 + 8 x - 20 x + 52 - 80 = 0
or
x^2 - 12 x - 28 = 0
go here
x = -2 or x = 14
use x = 14
y = 16(14) +104 = 328 ounces
or
y = -2 * 14^2 + 40 * 14 + 160 = -392 + 560 + 160 = 328 remarkable

Damon · Answer

https://www.mathsisfun.com/quadratic-equation-solver.html sorry, forgot quad eqn link

Joey · Answer

The answer is B 328

uh · Answer

thanks:)

jp · Answer

thanks i used 3 calculators and could not get the answer