HCl is a strong acid, so the pH=-log[Molarity of HCl]
Calculate the molarity of HCl
Molarity of HCl=[(0.87mL)*(1.979)]/12.96mL]
Plug in the numbers and solve.
Volume of distilled water used 12.09 mL
Volume of HCl added 0.87 mL
Concentration of added HCl 1.979 M
pH of diluted HCl solution ___________________
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