moles H2SO4 = M x L = 0.105*0.600 = ??
M = moles/L
You know moles and M, solve for L and convert to mL. Technically, this is the volume to which the H2SO4 must be diluted to make the final volume; however, the question asks for the amount of water that must be added. Therefore, assuming the volume are additive , you want the final volume you calculate -105 mL = amount to be added.
What volume, in millilitres, of distilled water must be added to 105 mL of 0.600 mol/L sulfuric acid solution in order to dilute it to a concentration of 0.400 mol/L
2 answers
much appreciated