To find the number of moles of potassium nitrate produced, we need to calculate the molar ratio between potassium phosphate (K3P04) and potassium nitrate (KNO3) using the balanced chemical equation given.
From the balanced chemical equation:
1 mole of K3P04 will produce 3 moles of KNO3.
First, we need to calculate the molar mass of K3P04:
K = 39.10 g/mol
P = 30.97 g/mol
O = 16.00 g/mol
Molar mass of K3P04 = 3(39.10) + 30.97 + 4(16.00) = 212.27 g/mol
Next, we need to calculate the number of moles of K3P04:
Mass of K3P04 = 67 grams
Number of moles = Mass / Molar mass
Number of moles = 67 g / 212.27 g/mol ≈ 0.315 moles
Finally, we can determine the number of moles of KNO3 produced using the molar ratio:
Number of moles of KNO3 = 0.315 moles of K3P04 * 3 moles KNO3 / 1 mole K3P04 = 0.945 moles
Therefore, when 67 grams of potassium phosphate (K3P04) react, 0.945 moles of potassium nitrate (KNO3) are produced.
Using this equation:
K3P04 + AI(N03)3 - 3KN03 + AIP04
How many moles of potassium nitrate (KNO3) are produced when 67 grams of potassium phosphate(K3P04) react?
1 answer
1 answer