Lead (II) nitrate as Pb(NO ) and potassium iodide as KI combine to form the products shown.

Question

2 KNO + PbI
How many moles of each reactant are involved in the reaction?
(1 point)
3 2
3 2
1 mole of lead (II) nitrate and 2 moles of potassium iodide
2 moles of lead (II) nitrate and 2 moles of potassium iodide
1 mole of lead (II) nitrate and 1 mole of potassium iodide
2 moles of lead (II) nitrate and 1 mole of potassium iodide

Answer 1

The chemical reaction between lead(II) nitrate (Pb(NO₃)₂) and potassium iodide (KI) is represented by the following balanced equation:

\[ \text{Pb(NO}_3\text{)}_2 + 2 \text{KI} \rightarrow \text{PbI}_2 + 2 \text{KNO}_3 \]

From this balanced equation, we can determine the moles of each reactant involved:

• 1 mole of lead(II) nitrate (Pb(NO₃)₂)
• 2 moles of potassium iodide (KI)

Thus, the correct answer is: 1 mole of lead (II) nitrate and 2 moles of potassium iodide.