To find the number of moles of each reactant involved in the reaction between lead (II) nitrate (Pb(NO₃)₂) and potassium iodide (KI), you can look at the balanced chemical equation for the reaction.
The balanced reaction is:
\[ 2 \text{KI} + \text{Pb(NO}_3\text{)}_2 \rightarrow 2 \text{KNO}_3 + \text{PbI}_2 \]
From this equation, you can see that:
- 1 mole of lead (II) nitrate (Pb(NO₃)₂) reacts with 2 moles of potassium iodide (KI).
Now, let's look at the options provided:
- 2 moles of lead (II) nitrate and 1 mole of potassium iodide
- 1 mole of lead (II) nitrate and 2 moles of potassium iodide
- 1 mole of lead (II) nitrate and 1 mole of potassium iodide
- 2 moles of lead (II) nitrate and 2 moles of potassium iodide
The correct response is:
1 mole of lead (II) nitrate and 2 moles of potassium iodide.
1 answer