First calculate the speed if earth in its orbit
V = 2 pi R / (3.1558*10^7 s)= ? m/s
(The denominator is 1 year expressed in seconds)
Then get the mass M of the sun from
M G/R^2 = V^2/R (centripetal acceleration)
Use the period of the earth (2.34 y), its
mean orbital radius (1.496 × 1011 m), and
the universal gravitational constant (6.673 × 10−11 N · m2/kg2) to calculate the mass of sun. Answer in units of kg.
6 answers
so is the correct answer 3.632308558 X 10 ^29 ???
The Sun's mass is 1.99 x 10^30 kg.
You made a mistake somewhere.
You made a mistake somewhere.
V = 2pi R/ 2.34(3.1558X 10^7s)
(2pi R/ 2.34(3.1558X 10^7s)^2 / 1.496X10^11 = ANS
ANS/ G/R^2 - > Ans/ (6.673X10^-11/1.496X10^11)
= 3.632308558 X 10^29
i did everything right i believe
(2pi R/ 2.34(3.1558X 10^7s)^2 / 1.496X10^11 = ANS
ANS/ G/R^2 - > Ans/ (6.673X10^-11/1.496X10^11)
= 3.632308558 X 10^29
i did everything right i believe
The problem is this: You used the wrong orbital period of the Earth. Did they really tell you it is 2.34 years? It is actually 1.000 years. That is the definition of a year!
The orbital radius and G value that you used are correct.
The orbital radius and G value that you used are correct.
yes its given as 2.34 years. its an online hw generator that gives everyone different sets of numbers.