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Molly86
Questions (2)
Use the period of the earth (2.34 y), its
mean orbital radius (1.496 × 1011 m), and the universal gravitational constant (6.673
6 answers
1,623 views
A long uniform rod of length 4.76 m and mass 5.48 kg is pivoted about a horizontal, frictionless pin through one end. The rod is
1 answer
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Answers (3)
yes its given as 2.34 years. its an online hw generator that gives everyone different sets of numbers.
V = 2pi R/ 2.34(3.1558X 10^7s) (2pi R/ 2.34(3.1558X 10^7s)^2 / 1.496X10^11 = ANS ANS/ G/R^2 - > Ans/ (6.673X10^-11/1.496X10^11) = 3.632308558 X 10^29 i did everything right i believe
so is the correct answer 3.632308558 X 10 ^29 ???
