Find the rotational kinetic energy of the earth about the sun due to its orbit about the sun. The mass of the earth M is 6 x 1024 kg, the orbital radius r is 1.5 x 1011 m and the rotational period T is 1 year. Treat the earth as a point mass in this problem

Answer 1

(1/2) I w^2

I = m r^2
= 6*10^24 * 1.5*10^11 * 1.5*10^11

w = 2 pi/T
= 2 pi/(1 yr * 365 d/yr *24hr/d*3600s/hr)

Answer 2

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