To find the total bond energy in the products of the reaction \( H_2 + Cl_2 \rightarrow 2 HCl \), we first need to look at the bonds formed in the products, which are the \( H–Cl \) bonds in the \( 2 HCl \) molecules.
Since there are 2 molecules of \( HCl \), the total bond energy for the \( H–Cl \) bonds will be:
\[ \text{Total bond energy in products} = 2 \times \text{Bond energy of } H–Cl \] \[ = 2 \times 427 , \text{kJ/mol} = 854 , \text{kJ/mol} \]
Thus, the total bond energy in the products of the reaction is 854 kJ/mol.