Use the information in the table to answer the question. Bond Bond Energy (kJ/mol) H-I 297 H-H 435 I-I 151 Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction. H2+I2→2HI How much total bond energy in kJ/mol is in the products of the reaction? (1 point) Responses 448 448 297 297 453 453 594

Answer 1

To determine the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2 HI \), we need to look at the bond energy of the bonds formed in the products.

The product of the reaction, hydroiodic acid (HI), contains two HI molecules. Given that the bond energy of the H-I bond is 297 kJ/mol, we can calculate the total bond energy for the two HI molecules formed.

Since there are 2 HI molecules, the total bond energy in kJ/mol for the products can be calculated as follows:

\[ \text{Total bond energy} = 2 \times \text{Bond energy of H-I} \] \[ \text{Total bond energy} = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]

Therefore, the total bond energy in the products of the reaction is 594 kJ/mol.