To find the total bond energy in the products of the given reaction, we first need to determine the number of bonds formed in the reaction:
The reaction is: \[ H_2 + I_2 \rightarrow 2 HI \]
In the reactants:
- 1 H-H bond is broken (bond energy = 435 kJ/mol)
- 1 I-I bond is broken (bond energy = 151 kJ/mol)
In the products:
- 2 H-I bonds are formed (bond energy = 297 kJ/mol each)
Now we calculate the total bond energy in the products:
Total bond energy in the products: \[ 2 \text{ H-I bonds} = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]
Therefore, the total bond energy in the products of the reaction is 594 kJ/mol.
So, the correct response is: 594