Use the information in the table to answer the question.

Bond Bond Energy ( kJ/mol
)
H-I
297

H-H
435

I-I
151

Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.

H2+I2→2HI


How much total bond energy in kJ/mol
is in the products of the reaction?

(1 point)
Responses

297
297

448
448

594
594

453

1 answer

To find the total bond energy in the products of the given reaction, we first need to determine the number of bonds formed in the reaction:

The reaction is: \[ H_2 + I_2 \rightarrow 2 HI \]

In the reactants:

  • 1 H-H bond is broken (bond energy = 435 kJ/mol)
  • 1 I-I bond is broken (bond energy = 151 kJ/mol)

In the products:

  • 2 H-I bonds are formed (bond energy = 297 kJ/mol each)

Now we calculate the total bond energy in the products:

Total bond energy in the products: \[ 2 \text{ H-I bonds} = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]

Therefore, the total bond energy in the products of the reaction is 594 kJ/mol.

So, the correct response is: 594

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