Use the information in the table to answer the question.

Question

Bond Bond Energy ( kJ/mol )
H-I 297
H-H 435
I-I 151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.

H2+I2→2HI

How much total bond energy in kJ/mol is in the products of the reaction?

(1 point)
Responses

448
448

594
594

453
453

297

Answer 1

To determine the total bond energy in the products of the reaction \( \text{H}_2 + \text{I}_2 \rightarrow 2 \text{HI} \), we need to calculate the bond energy of the products, which is \( 2 \times \text{Bond Energy of HI} \).

From the provided table, we have:

• The bond energy of \( \text{H-I} = 297 , \text{kJ/mol} \).

Since the reaction produces \( 2 , \text{HI} \), we calculate the total bond energy of the products as follows:

\[ \text{Total Bond Energy of Products} = 2 \times \text{Bond Energy of HI} = 2 \times 297 , \text{kJ/mol} \] \[ = 594 , \text{kJ/mol} \]

Therefore, the total bond energy in the products of the reaction is \( 594 , \text{kJ/mol} \).

The correct response is 594.