Use the information in the table to answer the question.

Question

Bond Bond Energy ( kJ/mol )
H-I 297
H-H 435
I-I 151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.

H2+I^2→2HI

How much total bond energy in kJ/mol is in the products of the reaction?

Answer 1

In the reaction \( H_2 + I_2 \rightarrow 2 HI \), we need to calculate the total bond energy in the products, which consist of 2 moles of hydroiodic acid (HI).

Given the bond energy for H-I is:

• H-I bond energy = 297 kJ/mol

Since in the products we have 2 moles of HI, we calculate the total bond energy in the products as follows:

\[ \text{Total bond energy in products} = 2 \times \text{Bond energy of HI} = 2 \times 297 \text{ kJ/mol} = 594 \text{ kJ/mol} \]

Thus, the total bond energy in the products of the reaction is 594 kJ/mol.