To find the total mass of the reactants in the given reaction:
\[ \text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl} \]
we first need to calculate the mass of each reactant based on the given atomic masses.
-
Iron chloride (FeCl3):
- 1 Fe atom = 56 amu
- 3 Cl atoms = 3 × 35 amu = 105 amu
- Total mass of FeCl3 = 56 amu + 105 amu = 161 amu
-
Water (H2O):
- 2 H atoms = 2 × 1 amu = 2 amu
- 1 O atom = 16 amu
- Total mass of H2O = 2 amu + 16 amu = 18 amu
Now, we can calculate the total mass of the reactants:
\[ \text{Total mass of reactants} = \text{mass of FeCl}_3 + \text{mass of 3H}_2\text{O} \] \[ \text{Total mass of reactants} = 161 \text{ amu} + 3 \times 18 \text{ amu} \] \[ \text{Total mass of reactants} = 161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu} \]
So, the total mass of the reactants is 215 amu.