Question

Use the equation and the table to answer the question.FeCl3 + 3H2O → Fe(OH)3 + 3HClElementMass of an Atom (amu)Fe56Cl35H1O16Iron chloride and water react according to the equation shown. The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?(1 point)Responses179 amu179 amu108 amu108 amu161 amu161 amu215 amu

Answer 1

To find the total mass of the reactants in the equation:

\[ \text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl} \]

we need to calculate the mass of each reactant.

1. Iron Chloride (FeCl₃):

   • Mass of Fe = 56 amu
   • Mass of Cl = 35 amu
   • Since there are 3 chlorine atoms: \[ \text{Mass of FeCl}_3 = \text{Mass of Fe} + 3 \times \text{Mass of Cl} = 56 + 3 \times 35 = 56 + 105 = 161 \text{ amu} \]

2. Water (H₂O):

   • Mass of H = 1 amu
   • Mass of O = 16 amu
   • Since there are 2 hydrogen atoms: \[ \text{Mass of H}_2\text{O} = 2 \times \text{Mass of H} + \text{Mass of O} = 2 \times 1 + 16 = 2 + 16 = 18 \text{ amu} \]

   Since there are 3 water molecules: \[ \text{Total mass of } 3\text{H}_2\text{O} = 3 \times \text{Mass of H}_2\text{O} = 3 \times 18 = 54 \text{ amu} \]

Now, we can find the total mass of the reactants:

\[ \text{Total mass of reactants} = \text{Mass of FeCl}_3 + \text{Total mass of } 3\text{H}_2\text{O} = 161 + 54 = 215 \text{ amu} \]

Thus, the total mass of the reactants is 215 amu.