To calculate the total mass of the reactants in the equation:
\[ \text{FeCl}_3 + 3\text{H}_2\text{O} \]
we first need to determine the mass of each reactant based on the provided atomic masses.
-
Calculate the mass of FeCl3:
- Iron (Fe) = 1 x 56 amu = 56 amu
- Chlorine (Cl) = 3 x 35 amu = 105 amu
- Total mass of FeCl3 = 56 amu + 105 amu = 161 amu
-
Calculate the mass of 3 H2O:
- Hydrogen (H) = 2 x 1 amu = 2 amu per water molecule
- Oxygen (O) = 1 x 16 amu = 16 amu per water molecule
- Total mass of one H2O molecule = 2 amu + 16 amu = 18 amu
- For 3 H2O: 3 x 18 amu = 54 amu
-
Total mass of reactants:
- Total mass of reactants = mass of FeCl3 + mass of 3H2O
- Total mass of reactants = 161 amu + 54 amu = 215 amu
Thus, the total mass of the reactants is 215 amu.
The correct answer is A. 215 amu.