Two ships leave a port at 9 a.m. One travels at a bearing of N 53° W at 12 miles per hour, and the other travels at a bearing of S 67° W at 19 miles per hour. Approximate how far apart they are at noon that day. (Round your answer to one decimal place.)

Answer 1

My quick sketch shows a triangle with sides 36 and 57
with a contained angle between those sides of 60°

So you have a clear case of the cosine law

x^2 = 36^2 + 57^2 - 2(36)(57)cos60°

carry on

Answer 2

Two ships leave a port at 9 a.m. One travels at a bearing of N 53° W at 8 miles per hour, and the other travels at a bearing of S 67° W at 19 miles per hour. Approximate how far apart they are at noon that day