Two ships leave from the same port. One ship travels on a bearing of 157 degrees at 20 knots. The second ship travels on a bearing of 247 degrees at 35 knots. (1 knot is a speed of 1 nautical mile per hour).

Question

Two ships leave from the same port. One ship travels on a bearing of 157 degrees at 20 knots. The second ship travels on a bearing of 247 degrees at 35 knots. (1 knot is a speed of 1 nautical mile per hour). 
Calculate the bearing of the second ship from the first, to the nearest minute.

Steve · Accepted Answer

The two courses are 90 degrees apart, so it's just a matter of figuring the angles of the right triangle. If the angle made by the 1st ship is θ, then the bearing of ship 2 from ship 1 is just

(157+180-θ)°

bobpursley · Answer

When? after two days? after two hours?

Carly · Answer

i dont know this was the question i got asked in my textbook and i really need help with this

marcus · Answer

wrong some how the answer is 276degrees and 45 min