A ship leaves port and travels 21km on a bearing of 032 degrees and then 45km on a bearing of 287 degrees. A. calculate it distance from the port. B. calculate the bearing of the port from the ship

Answer 1

21km on a HEADING of 032 degrees
distance north = 21 cos 32 = 17.8
distance West = -21 sin 32 (really east so negative) = -11.1

45km on a HEADING of 287 degrees (73 deg west of north)
distance north = 45 cos 73 = 13.2
distance west = 45 sin73 = 43.0

total north = 31
total west = 31.9

distance =sqrt (31^2 + 31.9^2) = 44.5
tan angle west of north = 31.9/31 = 1.03
so angle w of n = 45.8
360 - 45.8 = 314 deg bearing from start

Answer 2

314 - 180 = 134 is bearing of port from ship then