Let x be the number of minutes it takes for the two vats to have the same amount of liquid.
The amount of liquid in the first vat after x minutes is 6x gallons.
The amount of liquid in the second vat after x minutes is 28 + 4x gallons.
To find when the two vats have the same amount of liquid, we set the two expressions equal to each other:
6x = 28 + 4x
Subtracting 4x from both sides, we get:
2x = 28
Dividing by 2, we find:
x = 14
Therefore, it will take 14 minutes for the two vats to have the same amount of liquid.
two pumps are filling large vats of liquid one vat is empty and the pump is filling it at a rate of 6 gallons per minute the other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minutes when will the two vats have the same amount of liquid. use x as a your variable
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