Let's assume that after t minutes, the two vats will have the same amount of liquid.
Let V be the amount of liquid in the first vat after t minutes, and let W be the amount of liquid in the second vat after t minutes.
The amount of liquid in the first vat after t minutes is given by:
V = 6t
The amount of liquid in the second vat after t minutes is given by:
W = 28 + 4t
To find when the two vats have the same amount of liquid, we need to solve the equation:
V = W
6t = 28 + 4t
2t = 28
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes.
Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid?
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