Let's represent the time in minutes as 't'.
The amount of liquid in the first vat at time 't' can be represented as 6t (since it is filling at a rate of 6 gallons per minute).
The amount of liquid in the second vat at time 't' can be represented as 28 + 4t (since it already contains 28 gallons and is filling at a rate of 4 gallons per minute).
To find when the two vats have the same amount of liquid, we set them equal to each other:
6t = 28 + 4t
Simplifying, we get:
2t = 28
Dividing both sides by 2, we get:
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes.
Two pumps are filling large vats of liquid. One vat is empty and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid
2 answers
Y'all, it is 14.
I'm not sure if you're getting question 1 and question 4 mixed up.
because for question 1 it's:
6x = 10 + 4x
and for question 4 it's:
14
I'm not sure if you're getting question 1 and question 4 mixed up.
because for question 1 it's:
6x = 10 + 4x
and for question 4 it's:
14