Two pumps are filling large vats of liquid. One vat is empty and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid

2 answers

Let's represent the time in minutes as 't'.

The amount of liquid in the first vat at time 't' can be represented as 6t (since it is filling at a rate of 6 gallons per minute).

The amount of liquid in the second vat at time 't' can be represented as 28 + 4t (since it already contains 28 gallons and is filling at a rate of 4 gallons per minute).

To find when the two vats have the same amount of liquid, we set them equal to each other:

6t = 28 + 4t

Simplifying, we get:

2t = 28

Dividing both sides by 2, we get:

t = 14

Therefore, the two vats will have the same amount of liquid after 14 minutes.
Y'all, it is 14.
I'm not sure if you're getting question 1 and question 4 mixed up.

because for question 1 it's:
6x = 10 + 4x

and for question 4 it's:
14