Two Object Were Projected Vertically upward at different time with speed of 80m/s and 100m/s respectively. if the time interval is 2s. when and where will they meet .
4 answers
which one starts first...
surely the slower one is shot first (per the "respectively")
set their heights equal to find the time when they meet:
80t - 4.9t^2 = 100(t-2) - 4.9(t-2)^2
solve for t to find when
evaluate h(t) to find where
extra credit: is the first object rising or falling when they meet?
set their heights equal to find the time when they meet:
80t - 4.9t^2 = 100(t-2) - 4.9(t-2)^2
solve for t to find when
evaluate h(t) to find where
extra credit: is the first object rising or falling when they meet?
if the faster one goes 1st, they don't meet in flight
huh - I would not have guessed that.
In fact, if the slower one goes second, it needs to have an initial speed of at least 90.2 m/s for it to stay aloft long enough to meet the faster one before it hits in 20.48 seconds.
In fact, if the slower one goes second, it needs to have an initial speed of at least 90.2 m/s for it to stay aloft long enough to meet the faster one before it hits in 20.48 seconds.
1 answer