Asked by Habeeb
Two objects were projected vertically upward at different times with speed of 80m/s and 10m/s respectively,if the time interval is 2s. When and where would they meets
Answers
Answered by
oobleck
you want
10t - 4.9t^2 = 80(t-2) - 4.9(t-2)^2
solve for t
10t - 4.9t^2 = 80(t-2) - 4.9(t-2)^2
solve for t
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