Question
Two objects were
projected vertically
upwards at different
time with a speed ofTwo objects were
projected vertically
upwards at different
time with a speed of
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.? 65,485 results
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.? 65,485 results
projected vertically
upwards at different
time with a speed ofTwo objects were
projected vertically
upwards at different
time with a speed of
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.? 65,485 results
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.? 65,485 results
Answers
Two objects were
projected vertically
upwards at different
time with a speed ofTwo objects were
projected vertically
upwards at different
time with a speed of
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.?
projected vertically
upwards at different
time with a speed ofTwo objects were
projected vertically
upwards at different
time with a speed of
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.?
Two objects were
projected vertically
upwards at different
time with a speed ofTwo objects were
projected vertically
upwards at different
time with a speed of
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.? a
projected vertically
upwards at different
time with a speed ofTwo objects were
projected vertically
upwards at different
time with a speed of
80ms-¹ and 100ms-¹
respectively.if the time
interval is 2 sec,when
and where would they
meet.? a
geez - what do you have against just typing your stuff normally?
You want to find t where
80t - 4.9t^2 = 100(t-2) - 4.9(t-2)^2
then use that to find the height
You want to find t where
80t - 4.9t^2 = 100(t-2) - 4.9(t-2)^2
then use that to find the height
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