a particle is projected at an angle of 30 degree to the horizontal.

Question

(a), calculate the time of flight of the particle.
(b) speed of the particle at its maximum height

Answer 1

V defined as speed out of the barrel

time rising = time falling so find rise time and multiply by 2

vertical problem:
Vi = V sin 30 = .5 V

v = Vi - 9.8 t
v = 0 at top
0 = .5 V - 9.8 t
so
t = .5 V/9.8
and 2 t = total time aloft = V/9.8

at max height there is no vertical velocity v
so the total velocity is the horizontal velocity which does not change
so
u = V cos 30